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titanium?

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  • Jerkizoid
    replied
    So....

    Ti is weaker not stronger, so any advantage gained is only 1/2 the rotating weight? So if my bite is equal between the two the only gain is less weight?
    That could be a bunch, like 2 full pounds with steel being around 4 pounds and the Ti is 2. Guess I just have to test it and remove it before towing the boat anywhere!

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  • propfxrO84
    replied
    From a dummy that is a "prop" guy (5,000 propeller inventory) titanium is "OUT". Drop forged is "IN". You might Ask this one guy named Hering, see what he has to say about it. All the tech talk is fun and insightful but, the facts speak for themselves. No disrespect intended. BT

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  • LarryR
    replied
    Dohh! I missed that definition. My bad and thanks.

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  • ZUL8TR
    replied
    Clairification

    Originally posted by LarryR View Post
    That's interestin', and perhaps more useful than the answer to my question, which involved the ratio of SM to density. To Jerkizoid: As YellowJacket stated above, the "bendability" of a material goes with the modulus, not the strength. A Ti blade will bend more under the same load and geometry than any steel one, be it stainless or otherwise.
    SM = specific modulus = generally defined as the ratio of Modulus of elasticity to mass density as you stated in your riddle me this. This definition is predominately used for a stiffness driven design. However depending on what type of structural/dimensional constraints are placed on the design will determine the algebraic state of density in the denominator, i.e. density squared or density cubed. Other factors also play into the structural design along with the constraints selected.

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  • LarryR
    replied
    That's interestin', and perhaps more useful than the answer to my question, which involved the ratio of SM to density. To Jerkizoid: As YellowJacket stated above, the "bendability" of a material goes with the modulus, not the strength. A Ti blade will bend more under the same load and geometry than any steel one, be it stainless or otherwise.

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  • ZUL8TR
    replied
    specific modulus (SM)

    Originally posted by LarryR View Post
    Agree with both. The best use of CAD is to predict what is going to happen, find out what happens and then adjust the computer model to agree (after making sure that the test conditions, are truly represented by the model.) After all that, you can change the model incrementally to predict what changes will do, pretty accurately. Riddle me this: why do steel, aluminum, magnesium and titanium all have about the same ratio for modulus to density, while other metals generally do not?
    Don't recall the answer why the metals you list have the about the same SM but Osmium and Wrought (hand worked) Iron also have similar SM's. In the wood department dry Sitka Spruce has a similar SM to those metals. Those square rigged clipper builders knew what they were doing with the use of Sitka for selected parts as well as the wood/fabric plane designer/builders and the race boat builders.

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  • Jerkizoid
    replied
    Little know fact, the famous Lavey and Champion in its day ran a Titanium prop!! It doesnt flex like steel so the bite is always consistant with pitch and rake constant. When the boat was sold and later distroyed, the prop was returned to the manufacture and owner who paid the bill!!! just one of the tricks no one hears about!! Big bucks or contacts, has advantages!

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  • LarryR
    replied
    I've tried a few time myself. no luck.

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  • Yellowjacket
    replied
    Originally posted by LarryR View Post
    Neither has anyone else that I have asked in the last 45-years, but thanks for thinkin' about it. -LarryR
    That's one of those things that you live with every day and don't think about, it just is... We used to use design the aerodynamics of stages in the compressor and do the stress and vibration analysis and then pick the material (Ti, SS or Ni) later. Didn't make much difference which you used, all the vibratory modes stayed in the same place since the modulus to density stayed the same..

    I was thinking it had to do with the fundamental crystalline structure of metals, which it still could. I recall something about it my materials course but that was about the same 45 years ago and in the fog of time....

    I was hoping you would give me the answer. I looked for a bit on the web and didn't see anything.

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  • LarryR
    replied
    Neither has anyone else that I have asked in the last 45-years, but thanks for thinkin' about it. -LarryR

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  • Jerkizoid
    replied
    Interesting

    WOW, thanks for that info! Kinda figured the strength characteristic but was shy of the workability factor but still a profile cut is an easy option for future tuning. Diameter and pitch is exactly what I ran with some success.... it is certainly going to be tested and i am thrilled its profile and design resembles the Italian Cary or Record brand configuration. Interesting also is the ID numbers are S/N (Ski class Nostalgia?) 057, my boat number! Nothing appears in the usual hub area but on the front flange. I'll get a picture.
    Thanks again, I figured the Outboards had Ti experience/knowledge.

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  • Yellowjacket
    replied
    Originally posted by LarryR View Post
    Agree with both. The best use of CAD is to predict what is going to happen, find out what happens and then adjust the computer model to agree (after making sure that the test conditions, are truly represented by the model.) After all that, you can change the model incrementally to predict what changes will do, pretty accurately. Riddle me this: why do steel, aluminum, magnesium and titanium all have about the same ratio for modulus to density, while other metals generally do not?
    Those materials all have the same density to modulus ratio because they all have the same kind of crystalline structure (body centered cubic IIRC, but it's be more than 44 years since I looked that stuff up so it might not be but that's what I remember)....

    Actually that's wrong....and they don't have the same crystalline structure...

    I don't know why they have the same modulus to density ratio...
    Last edited by Yellowjacket; 01-13-2014, 11:46 AM. Reason: wrong...

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  • LarryR
    replied
    Agree with both. The best use of CAD is to predict what is going to happen, find out what happens and then adjust the computer model to agree (after making sure that the test conditions, are truly represented by the model.) After all that, you can change the model incrementally to predict what changes will do, pretty accurately. Riddle me this: why do steel, aluminum, magnesium and titanium all have about the same ratio for modulus to density, while other metals generally do not?

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  • raceright
    replied
    That's nice all the computer ideas. And yes these props are costly so call Harry of Craig or Ron and use there props. Just sayinglololo

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  • Yellowjacket
    replied
    Originally posted by raceright View Post
    As with all things boatracin put in on the boat and try it...only sure way.
    With the capability of computers nowadays, you could actually model a conventional blade and a Ti blade and figure out what each would do in response to the forces crated by the water. It wouldn't be cheap, but that is exactly what we do to design turbines (using air of course).

    Hard to tell what is less costly, doing it on the computer or doing it in the water. If you had a huge budget or are doing it as a business, you would for sure do it on the computer first because you could do a bunch of iterations and get a lot closer to what you at least thought was really good. If you already have all the very expensive tools for the CFD analysis and the CAD analysis you could do it pretty easily, and probably get some good results right out of the box.

    After that, of course you have to test, but doing the analysis first can get you a lot closer to where you wanted to be, and it could reduce the amount of testing considerably.

    We are designing a small waterjet with a major waterjet company and before we test anything we are doing CFD analysis on the design and then we will test.

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